The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF).

(0) Obligation:

Runtime Complexity TRS:
The TRS R consists of the following rules:

f(f(0, x), 1) → f(g(f(x, x)), x)
f(g(x), y) → g(f(x, y))

Rewrite Strategy: FULL

(1) DecreasingLoopProof (EQUIVALENT transformation)

The following loop(s) give(s) rise to the lower bound Ω(n¹):
The rewrite sequence
f(g(x), y) →⁺ g(f(x, y))
gives rise to a decreasing loop by considering the right hand sides subterm at position [0].
The pumping substitution is [x / g(x)].
The result substitution is [ ].

(2) BOUNDS(n^1, INF)

(3) RenamingProof (EQUIVALENT transformation)

Renamed function symbols to avoid clashes with predefined symbol.

(4) Obligation:

Runtime Complexity Relative TRS:
The TRS R consists of the following rules:

f(f(0', x), 1') → f(g(f(x, x)), x)
f(g(x), y) → g(f(x, y))

S is empty.
Rewrite Strategy: FULL

(5) TypeInferenceProof (BOTH BOUNDS(ID, ID) transformation)

Infered types.

(6) Obligation:

TRS:
Rules:
f(f(0', x), 1') → f(g(f(x, x)), x)
f(g(x), y) → g(f(x, y))

Types:
f :: 0':1':g → 0':1':g → 0':1':g
0' :: 0':1':g
1' :: 0':1':g
g :: 0':1':g → 0':1':g
hole_0':1':g1_0 :: 0':1':g
gen_0':1':g2_0 :: Nat → 0':1':g

(7) OrderProof (LOWER BOUND(ID) transformation)

Heuristically decided to analyse the following defined symbols:
f

(8) Obligation:

TRS:
Rules:
f(f(0', x), 1') → f(g(f(x, x)), x)
f(g(x), y) → g(f(x, y))

Types:
f :: 0':1':g → 0':1':g → 0':1':g
0' :: 0':1':g
1' :: 0':1':g
g :: 0':1':g → 0':1':g
hole_0':1':g1_0 :: 0':1':g
gen_0':1':g2_0 :: Nat → 0':1':g

Generator Equations:
gen_0':1':g2_0(0) ⇔ 1'
gen_0':1':g2_0(+(x, 1)) ⇔ g(gen_0':1':g2_0(x))

The following defined symbols remain to be analysed:
f

(9) RewriteLemmaProof (LOWER BOUND(ID) transformation)

Proved the following rewrite lemma:
f(gen_0':1':g2_0(+(1, n4_0)), gen_0':1':g2_0(b)) → *3_0, rt ∈ Ω(n4₀)

Induction Base:
f(gen_0':1':g2_0(+(1, 0)), gen_0':1':g2_0(b))

Induction Step:
f(gen_0':1':g2_0(+(1, +(n4_0, 1))), gen_0':1':g2_0(b)) →_R^Ω(1)
g(f(gen_0':1':g2_0(+(1, n4_0)), gen_0':1':g2_0(b))) →_IH
g(*3_0)

We have rt ∈ Ω(n¹) and sz ∈ O(n). Thus, we have irc_R ∈ Ω(n).

(10) Complex Obligation (BEST)

(11) Obligation:

TRS:
Rules:
f(f(0', x), 1') → f(g(f(x, x)), x)
f(g(x), y) → g(f(x, y))

Types:
f :: 0':1':g → 0':1':g → 0':1':g
0' :: 0':1':g
1' :: 0':1':g
g :: 0':1':g → 0':1':g
hole_0':1':g1_0 :: 0':1':g
gen_0':1':g2_0 :: Nat → 0':1':g

Lemmas:
f(gen_0':1':g2_0(+(1, n4_0)), gen_0':1':g2_0(b)) → *3_0, rt ∈ Ω(n4₀)

Generator Equations:
gen_0':1':g2_0(0) ⇔ 1'
gen_0':1':g2_0(+(x, 1)) ⇔ g(gen_0':1':g2_0(x))

No more defined symbols left to analyse.

(12) LowerBoundsProof (EQUIVALENT transformation)

The lowerbound Ω(n¹) was proven with the following lemma:
f(gen_0':1':g2_0(+(1, n4_0)), gen_0':1':g2_0(b)) → *3_0, rt ∈ Ω(n4₀)

(13) BOUNDS(n^1, INF)

(14) Obligation:

TRS:
Rules:
f(f(0', x), 1') → f(g(f(x, x)), x)
f(g(x), y) → g(f(x, y))

Types:
f :: 0':1':g → 0':1':g → 0':1':g
0' :: 0':1':g
1' :: 0':1':g
g :: 0':1':g → 0':1':g
hole_0':1':g1_0 :: 0':1':g
gen_0':1':g2_0 :: Nat → 0':1':g

Lemmas:
f(gen_0':1':g2_0(+(1, n4_0)), gen_0':1':g2_0(b)) → *3_0, rt ∈ Ω(n4₀)

Generator Equations:
gen_0':1':g2_0(0) ⇔ 1'
gen_0':1':g2_0(+(x, 1)) ⇔ g(gen_0':1':g2_0(x))

No more defined symbols left to analyse.

(15) LowerBoundsProof (EQUIVALENT transformation)

The lowerbound Ω(n¹) was proven with the following lemma:
f(gen_0':1':g2_0(+(1, n4_0)), gen_0':1':g2_0(b)) → *3_0, rt ∈ Ω(n4₀)

(16) BOUNDS(n^1, INF)